I keep getting a syntax error for this block of code and I do not know why. elif(int(numRooms) >= 20)
print("you get a 20% discount")
discountPercent=20

elif(int(numRooms)>=10)
print("you get a 10% discount")
discountPercent=10

Statment expected, found Py:ELIF_KEYWORD

A.) generate scaffolding to create database for your application. develop all the entities identified in assignment #2. add any additional that may be identified later. b.) add data validation rules to the models that are appropriate for your application and data. c.) create links for each scaffold in the header section. part 2: application updates [30 points] a.) add two additional views to the "home" controller you created in assignment #1. b.) the two views should be named as “privacy" and "". c.) link the two newly created views in the footer section. hint: you would need to modify the “home" controller definition and create “privacy.html.erb" and “.html.erb" files in appropriate locations.

2. fabulously fit offers memberships for$35 per month plus a $50 enrollmentfee. the fitness studio offersmemberships for $40 per month plus a$35 enrollment fee. in how many monthswill the fitness clubs cost the same? what will the cost be?

When making changes to optimize part of a processor, it is often the case that speeding up one type of instruction comes at the cost of slowing down something else. for example, if we put in a complicated fast floating-point unit, that takes space, and something might have to be moved farther away from the middle to accommodate it, adding an extra cycle in delay to reach that unit. the basic amdahl's law equation does not take into account this trade-off. a. if the new fast floating-point unit speeds up floating-point operations by, on average, 2ă—, and floating-point operations take 20% of the original program's execution time, what is the overall speedup (ignoring the penalty to any other instructions)? b. now assume that speeding up the floating-point unit slowed down data cache accesses, resulting in a 1.5ă— slowdown (or 2/3 speedup). data cache accesses consume 10% of the execution time. what is the overall speedup now? c. after implementing the new floating-point operations, what percentage of execution time is spent on floating-point operations? what percentage is spent on data cache accesses?