Which option is better?
Option 1:
double d1 = 0.1; double d2 = 0.2; double d3 = 0.3; double x...
Computers and Technology, 28.02.2021 17:20 lollollollollol1
Which option is better?
Option 1:
double d1 = 0.1; double d2 = 0.2; double d3 = 0.3; double x = (d1 + d2) + d3 ; double y = d1 + (d2 + d3); if (x == y) {System. out. println("Equal");}
Option 2:
double d1 = 0.1; double d2 = 0.2; double d3 = 0.3; double x = (d1 + d2) + d3 ; double y = d1 + (d2 + d3); double z = x - y; double epsilon = 1E-5; if (java. lnag. Math. abs(z) < epsilon) {System. out. println("Equal");}
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