Consider the directed capacity graph given by V={0, 1, 2, 3, 4}, E={[0,1:3], [0,3:3], [1,2:4], [1,3:2], [2,4:4], [3,2:3], [3,4:2] } where [i, j:c] is shorthand for edge [i, j] having capacity c. Apply the Edmunds-Karp algorithm (BFS) to determine the maximum flow from vertex 0 (source) to vertex 4 (sink). Process lowest numbered vertex first in case of a tie. For each step of the algorithm, sketch the augmenting path and the flow associated there with as well as the total flow and residual capacity graphs.

Required:
Determine min cut sets S and T.

It is vital to research each of the services you plan to disable before implementing any change, especially on critical machines such as the: a. servers in the test environment. b. domain controller and other infrastructure servers. c. desktops that have previously been attacked. d. desktops used by upper-level management.

For a typical middle-income family, what is the estimated cost of raising a child to the age of 18? $145,500 $245,340 $304,340 $455,500

This question involves a class named textfile that represents a text file. public class textfile { private string filename; private string filename; private arraylist words; // constructors not shown // postcondition: returns the number of bytes in this file public int filesize() { } // precondition: 0 < = index < words.size() // postcondition: removes numwords words from the words arraylist beginning at // index. public void deletewords(int index, int numwords) { } // precondition: 0 < = index < = words.size() // postcondition: adds elements from newwords array to words arraylist beginning // at index. pub lic voidaddwords(int index, string[] newwords) { } // other methods not shown } complete the filesize() method. the filesize() is computed in bytes. in a text file, each character in each word counts as one byte. in addition, there is a space in between each word in the words arraylist, and each of those spaces also counts as one byte. for example, suppose the words arraylist stores the following words: { mary had a little lamb; its fleece was white as snow. } the filesize() method would compute 4 + 3 + 1 + 6 + 5 + 4 + 6 + 3 + 5 + 2 + 5 as the sum of the lengths of each string in the arraylist. the value returned would be this sum plus 10, because there would also be 10 spaces in between the 11 words. complete the filesize() method below: // postcondition: returns the number of bytes in this file public int filesize() { }