Write program statements to determine the fewest number of bills needed to represent a total dollar amount.

I guess, you ned it on Java. Check this code. I hope you'll find it helpful: 

public class TRY{ 
public static void main(String[] args) {

double MONEY, QUARTERS, DIMES, NICKELS, PENNIES; 
int DOLLAR_100, DOLLAR_50, DOLLAR_20, DOLLAR_10, DOLLAR_5, DOLLAR_1; 

Scanner Scan = new Scanner(System.in); 

System.out.print("Enter the monetary amount in xx.xx: " ); 
MONEY = Scan.nextFloat(); 

DOLLAR_100 = (int) (MONEY / 100); 
DOLLAR_50 = (int) (MONEY % 100 / 50); 
DOLLAR_20 = (int) (MONEY % 100 % 50 / 20); 
DOLLAR_10 = (int) (MONEY % 100 % 50 % 20 / 10); 
DOLLAR_5 = (int) (MONEY % 100 % 50 % 20 % 10 / 5); 
DOLLAR_1 = (int) (MONEY % 100 % 50 % 20 % 10 % 5); 
QUARTERS = Math.round( (MONEY % 100 % 50 % 20 % 10 % 5 % 1 / 0.25)); 
DIMES = Math.round((MONEY % 100 % 50 % 20 % 10 % 5 % 1 % 0.25 / 0.10)); 
NICKELS = Math.round((MONEY % 100 % 50 % 20 % 10 % 5 % 1 % 0.25 % 0.10 / .05)); 
PENNIES = Math.round((MONEY % 100 % 50 % 20 % 10 % 5 % 1 % 0.25 % 0.10 
% .05 / .01)); 

System.out.println(DOLLAR_100 + " hundred dollar bills" ); 
System.out.println(DOLLAR_50 + " fifty dollar bills" ); 
System.out.println(DOLLAR_20 + " twenty dollar bills" ); 
System.out.println(DOLLAR_10 + " ten dollar bills" ); 
System.out.println(DOLLAR_5 + " five dollar bills" ); 
System.out.println(DOLLAR_1 + " one dollar bills" ); 
System.out.println((int) QUARTERS + " quarters" ); 
System.out.println((int) DIMES + " dimes" ); 
System.out.println((int) NICKELS + " nickels" ); 
System.out.println((int) PENNIES + " pennies" ); 
System.out.println("Money left after % by 100: " + MONEY % 100); 
} 
} 

Huhuhubuhuhuhuhuhuh ya um

B, it is easy to scan for key information. there are times when a lot of information is included in a business letter. the block letter format you find key bits of information quickly, without having to read through the whole paper.