You're a swimmer, and you want to compare all of your race times to find the fastest one. write a program that continuously takes race times as doubles from standard input, until the input is no more races, at which point it should print out the time of your fastest race.

To find the fastest race among the entire race, enter the race time in seconds and make a list to store them. After that create a loop that will continue till the last race is not completed. Now, compare the race times . In main function, enter the race time or enter no more races. Finally, print the fastest race value. The easiest code in python language is written below in MaxRace.py file.

Further explanation:

Code: MaxRace.py

raceTime=Input(“Enter the race time or enter ‘no more races’:”)

if raceTime!=”no more races”:

fastest_race_time=float(raceTime)

# compare the race times

while raceTime!=’no more races’:

compareTime=float(raceTime)

if fastest_race_time>compareTime:

fastest_race_time=compareTime

raceTime=input(“Enter the race time or enter ‘no more races’:  “)

#print the fastest race

print(fastest_race_time)

else:

print(raceTime)

Output:

Run the commands in python, the output will be looking as below:

Enter the race time or enter ‘no more races’: 49.0

Enter the race time or enter ‘no more races’: 52.0

Enter the race time or enter ‘no more races’: 39.0

Enter the race time or enter ‘no more races’: 23.6

52.0

Learn more:

1. A company that allows you to license software monthly to use online is an example of ?  

2. Prediction accuracy of a neural network depends on and .  

Answer details:

Grade: College Engineering

Subject: Computer Science and Engineering

Chapter: Python Programming

Keyword:

Python, input, output, programming, statements,  loops, if-else, print,  while, body, main body, char, int, float, variables, race, time, maximum, compare, code, fastest, seconds

answer: internal fragmentation is the difference between the (fixed) size of a memory hole and the data within in that memory. for example, if a 1,024 byte block of memory holds 800 bytes of data, then the 224 bytes difference is considered lost to internal fragmentation.

external fragmentation occurs when the sum of memory fragments is large enough to satisfy a request, but the holes are non-contiguous and the request cannot be satisfied. this can occur when memory is dynamically allocated and freed.

explanation: