Consider the usual algorithm for determining whether a sequence of parentheses is balanced. What is the maximum number of parentheses that will appear on the stack AT ANY ONE TIME when the algorithm analyzes: (()(())(())) a. 1
b. 2
c. 3
d. 4

There is a simple pattern for determining if a binary number is odd. what is it and why does this pattern occur? how many bits would you need if you wanted to have the ability to count up to 1000? how high could you count in binary if you used all 10 of your fingers as bits? (finger up means 1, finger down means 0)

Agood flowchart alludes to both the inputs and outputs you will need to receive and give to the user. true or false?

What is the worst-case complexity of the maxrepeats function? assume that the longest string in the names array is at most 25 characters wide (i.e., string comparison can be treated as o( class namecounter { private: int* counts; int nc; string* names; int nn; public: namecounter (int ncounts, int nnames); int maxrepeats() const; }; int namecounter: : maxrepeats () { int maxcount = 0; for (int i = 0; i < nc; ++i) { int count = 1; for (int j = i+1; j < nc; ++j) { if (names[i] == names[j]) ++count; } maxcount = max(count, maxcount); } return maxcount; }