Determine exactlyhow many instruction cycles the delay loop in the code below (between the comment lines Begin Delay Loop and End Delay Loop) takes as a function of the variables Count1 and Count2. MaxCount EQU H'OA' ; Equates are good for defining literals
CBLOCK H'20 ; A CBL0CK defines a sequential region
Count1 ; Count 1 is in location H,20%
Count2 ; Count2 is in location H'21'
Scratch ; Scratch is in lication H'22'
ENDC ; ENDC ends the definition block
ORG 0x0000
GOTO Init
Init ORG 0x0008
BSF STATUS, RPO
CLRF TRISE
CLRF ANSEL
BCF STATUS, RPO
SetScr MOVLW H' 01'
MOVWF Scratch
MainLoop MOVF Scratch, W
MOVWF PORTB
; Begin Delay Loop
MOVLW Count 2
MOVWF Index2
Loop MOVLW Count1
MOVWF Index1
SubLoop NOP
NOP
DECFSZ Index1, F
GOTO SubLoop
DECFSZ Index2, F
GOTO Loop
; End Delay Loop
RRFScratch, F
ANDWF Scratch, F
BTFSC STATUS, Z
GOTO SetScr
GOTO MainLoop
Finish END
Explain what the program does, in a few sentences. In particular, what would be the purpose or result of the operations