g Write a function named find_min that takes two numbers as arguments and returns the minimum of the two. (Behavior is not specified for which to return, if they are even -- we won't test that case.) For example: Given 2 and 4, the function returns 2 as the minimum.

Following are the code to the given question:

#include <iostream>//header file

using namespace std;

void find_min(int x,int y)//defining a method find_min that takes two parameters

{

   if(x<y)//use if to check x less than y

   {

       cout<<x;//print value x

   }

   else//else block

   {

       cout<<y;//print value y

   }

}

int main()//main method

{

   int x,y;//defining integer variable

   cout<<"Enter first number: ";//print message

   cin>>x;//input value

   cout<<"Enter second number: ";//print message

   cin>>y;//input value

   find_min(x,y);//calling method

   return 0;

}

Output:

Enter first number: 4  

Enter second number: 2  

2

Explanation:

In this code, a method "find_min" that takes two integer variable "x,y" in its parameters and use if block to check its value and print is value.

In the main method, we declared two integer variable "x,y" that takes value from user-end, and pass the value into the method that prints its calculated value.

i've had the same problem. i generally just ignore it, as a ton of these "verified answers" are completely wrong.