2- Write aC+ program that calculates the sum of all even numbers from [1000,2000], using the while loop.

#include <iostream>

using namespace std;

int main() {  

 int n = 1000;

 int sum = 0;

 while(n <= 2000) {

   sum += n;

   n += 2;

 }

 cout << "sum of even numbers in [1000..2000] = " << sum << endl;

}

Explanation:

This will output:

sum of even numbers in [1000..2000] = 751500

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