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Given the following code and considering things like ASCII values and pointer addresses: int num1 = 5; //addressed at 1767612
int num2 = 10; //addressed at 1767600
int num3 = 15; //addressed at 1767588
char ch1 = ‘a’; //addressed at 3734375
char ch2 = ‘b’; //addressed at 3734363
char ch3 = ‘c’; //addressed at 3734351
char* chPtr = &ch3;
int* iPtr = &num3;
*iPtr = num3 * 8;
*chPtr = *iPtr;
What will the following statement output?
cout << ch3;
'c'
'P'
'x'
3734351
120

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Answers: 1

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