Given the snippet of code: int x = 5; int bar(int j) { int *k = 0, m = 5; k = &m; return (j+m); } void main(void) { static int i =0; i++; i = bar(i) + x; } Which variables obtain their memory from the stack? A. iB. jC. kD. mE. x

Variables j , k , m will be stored in the stack.

Explanation:

Variable x will not be in stack as is it a global variable.

Variable i will not be in stack as is it a static variable.

Variable j will be in stack as is it a local variable in the function.

Variable m will be in stack as is it a local variable in the function.

Variable k , a pointer will be in stack as it is in the function bar locally.

try restarting the ps as a whole. i have one and i recently had the same issue, if that doesn't work it may be that your dad need to renew the contract.

explanation:

answer: a, c

divide any of the y values by x values and you will always get 3 is the most simple way i can put it for you.