CLS
N = 1
FOR J = 1 TO 5
PRINT N
N = 10*N+1
NEXT J
END

1

11

111

1111

11111

Explanation:

Given

The above QBasic code

Required

The output

The iteration on the third line is repeated 5 times; i.e. for values of j from 1 to 5.

In each iteration, the value of N is printed and the next value is calculated.

Initially, the value of N is 1 ---- on line 2

So, 1 is printed first. The next value of N is as follows:

--- we keep replacing N (on the right-hand side) with current N value.

So, we have:

answer; i believe the correct answer is (b) by using a multimeter;