Using x86 assembly language, Write a program that converts an integer from -100 to 100 to text.
Below is a partial algorithm to convert an integer to text:
idiv user's number by 10 and store eax into variable Quotient and edx into Remainder
compare Quotient to 2 and jump to Twenty if equal; compare Quotient to 3 and jump to Thirty if equal; etc.
Twenty:
Output "twenty"
Jump to OnesDigit
Thirty:
Output "thirty"
Jump to OnesDigit
OnesDigit:
compare Remainder to 1 and jump to One if equal; compare Remainder to 2 and jump to Two if equal; etc.
One:
Output "one"
Jump to Ending
Two:
Output "two"
Jump to Ending
Example outputs
This x86 assembly program converts an integer to text.
Enter an integer from -100 to 100: 73
seventy-three
Enter an integer from -100 to 100: -100
negative one hundred
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format PE console
include win32ax. inc!
start:
ask user to enter a number
mov [Num), -25
print negative is less than 0
cmp [Num], o
jge positive
cinvoke printf,
negative neg [Num]
positive;
mov EAX, [Num]
cda
mov EBX, 10
idiv EBX
mov [Q], EAX
mov [R], EDX
twenty
cmp [Q), 2
jne thirty
cinvoke printf, "twenty"
invoke Sleep, -1