Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex: If userValues is {2, 2, 1, 2} and matchValue is 2 , then numMatches should be 3. Your code will be tested with the following values:
* matchValue: 2, userValues: {2, 2, 1, 2} (as in the example program above)
* matchValue: 0, userValues: {0, 0, 0, 0}
* matchValue: 50, userValues: {10, 20, 30, 40}
#include
#include
using namespace std;
int main() {
const int NUM_VALS = 4;
int matchValue;
unsigned int i;
int numMatches = -99; // Assign numMatches with 0 before your for loop
vector userValues(NUM_VALS);
cin >> matchValue;
for (i = 0; i < userValues. size(); ++i) {
cin >> userValues. at(i);
}
/* Your solution goes here */
cout << "matchValue: " << matchValue << ", numMatches: " << numMatches << endl;
return 0;
}

Write a program called assignment3 (saved in a file assignment3.java) that computes the greatest common divisor of two given integers. one of the oldest numerical algorithms was described by the greek mathematician, euclid, in 300 b.c. it is a simple but very e↵ective algorithm that computes the greatest common divisor of two given integers. for instance, given integers 24 and 18, the greatest common divisor is 6, because 6 is the largest integer that divides evenly into both 24 and 18. we will denote the greatest common divisor of x and y as gcd(x, y). the algorithm is based on the clever idea that the gcd(x, y) = gcd(x ! y, y) if x > = y and gcd(x, y) = gcd(x, y ! x) if x < y. the algorithm consists of a series of steps (loop iterations) where the “larger” integer is replaced by the di↵erence of the larger and smaller integer. this continues until the two values are equal. that is then the gcd.

Jace needs to answer a question on square roots to win a quiz. how can he use a spreadsheet to find the square root of 786? a. use the functions round and count b. create a table and chart c. use the function sqrt d. use the function now

3.11.3 quiz: comparing and analyzing function typesquestion 4 of 102 pointswhat can you say about the y-values of the two functions f(x) = 3x2-3 andg(x)=2* - 3?