Given s and x, determine the zero-based index of the first occurrence of xin s. o Strings consists of lowercase letters in the range asciifa-z). • String x consists of lowercase letters and may also contain a single wildcard character, that represents any one character. 1 > #include int main() 1 N Example s="xabcdey" x="abde" I The first match is at index 1. s X b c d х b d Index 0 1 2 3 4 Function Description Complete the function firstOccurrence in the editor below. The function must return an integer denoting the zero-based index of the first occurrence of string xins, if x is not in return - 1 instead Test Results Custom Inp . Type here to search 1h 6m left Language C firstOccurrence has the following parameter(s) strings a string of lowercase letters string x: a string of lowercase letters which may contain 1instance of the wildcard character Returns: int: the index of the first occurrence, or if x does not occur in s ALL Constraints Islength of s5x10 Is length of Xs 1000 1 > #include

This question involves a class named textfile that represents a text file. public class textfile { private string filename; private string filename; private arraylist words; // constructors not shown // postcondition: returns the number of bytes in this file public int filesize() { } // precondition: 0 < = index < words.size() // postcondition: removes numwords words from the words arraylist beginning at // index. public void deletewords(int index, int numwords) { } // precondition: 0 < = index < = words.size() // postcondition: adds elements from newwords array to words arraylist beginning // at index. pub lic voidaddwords(int index, string[] newwords) { } // other methods not shown } complete the filesize() method. the filesize() is computed in bytes. in a text file, each character in each word counts as one byte. in addition, there is a space in between each word in the words arraylist, and each of those spaces also counts as one byte. for example, suppose the words arraylist stores the following words: { mary had a little lamb; its fleece was white as snow. } the filesize() method would compute 4 + 3 + 1 + 6 + 5 + 4 + 6 + 3 + 5 + 2 + 5 as the sum of the lengths of each string in the arraylist. the value returned would be this sum plus 10, because there would also be 10 spaces in between the 11 words. complete the filesize() method below: // postcondition: returns the number of bytes in this file public int filesize() { }