Write a program that will take an integer and add up each of the number’s digits, count the number of digits in the number, and then average the digits. you must use a while loop and % to access each of the individual digits. use / to reduce the number so that you can average all of the digits. example: num = 123 can be taken apart with tempnum = 123 % 10 (which will pull off the 3), then tempnum = tempnum / 10 (will result in 12). do this in a loop while the number is > 0.   sample data : 234 10000 111 9005 84645 8547 123456789      be sure to include print statements that will format the output as below. sample output : 234 has a digit average of 3.0   10000 has a digit average of 0.2   111 has a digit average of 1.0   9005 has a digit average of 3.5   84645 has a digit average of 5.4   8547 has a digit average of 6.0   123456789 has a digit average of 5.0

Here is my solution:

import java.lang.System.*;

public class DigiMath {   

private static int countDigits(int number)
{
       int sum = 0;
       while(number > 0)
       {
           sum ++;
           number /= 10;
       }       return sum;   
}

private static int sumDigits(int number)   
{       
      int sum = 0;       
      while(number > 0) {
           sum += number % 10;
           number /= 10;
       }
       return sum;
}
   
   public static double averageDigits( int number )
   {
       int count = countDigits(number);
       if (count > 0) {
           return (double)sumDigits(number) / (double)count;      
       } else { 
            return 0; 
       } 
   }
   
   public static void PrintDigitAverage(int number)
   {
       System.out.printf("%d has a digit average of %1.1f\n", number, averageDigits(number));
   }
   
   public static void main(String[] args) 
   {
       // Method tests (run with java -ea)
       assert countDigits(12345) == 5 : "countDigits returns wrong count";
       assert sumDigits(12345) == 15 : "sumDigits returns wrong sum";
       assert averageDigits(12345) == 3.0: "averageDigits returns wrong average";

        PrintDigitAverage(234);
        PrintDigitAverage(10000); 
        PrintDigitAverage(111); 
        PrintDigitAverage(9005); 
        PrintDigitAverage(84645); 
        PrintDigitAverage(8547); 
        PrintDigitAverage(123456789);
   }
}

The answer is authorise net.