If you add 10 j of heat to a system so that the final temperature of the system is 200k, what is the change in entropy of the system? a)-0.05 j/k b)-0.30 j/k c)-1 j/k d)-9 j/k e)-2000 j/k

0.05 J/K

Explanation:

Given data in question

heat (Q) = 10 J

temperature (T) = 200 K

to find out

the change in entropy of the system

Solution

we will solve this by the entropy change equation

i.e  ΔS = ΔQ/T           1

put the value of heat Q and Temperature T in equation 1

ΔS is the enthalpy change and T is the temperature

so  ΔS = 10/200

ΔS = 0.05 J/K

it was a fall down when it happens

explanation:

answer:

can you answer my question?

explanation: