Aparticle moves along a circular path of radius 300 mm. if its angular velocity is θ = (2t) rad/s, where t is in seconds, determine the magnitude of the particle's acceleration when t= 2 s.

4.83m/

Explanation:

For a particle moving in a circular path the resultant  acceleration at any point is the vector sum of radial and the tangential acceleration

Radial acceleration is given by r

Applying values we get  X0.3m

Thus

At time = 2seconds

The tangential acceleration is given by

Thus the resultant acceleration is given by

answer:

put more,

answer:

6.3 is the answer

explanation:

because it is the ex