The surface area of the lifting piston in a forklift truck 0.008 m2. the maximum load on the platform is 1250 kg. the lifting mechanism, which also has to be raised, weighs 6000 n the minimum pressure on the piston must therefore be

minimum pressure on the piston is 2281.25 KPa

Explanation:

Given data in question

surface area ( A ) =  0.008 m²

load ( L1) = 1250 kg  

weight ( W ) = 6000 N

to find out

minimum pressure on the piston

Solution

we have given load and weight

so total force acting on it load +weight

total force = 1250 kg + 6000 N

total force = 12250 N + 6000 N   = 18250 N

convert 1250 kg = 12250 N

Now we apply power formula i.e.

power = force / area

put the value force and area in power equation

power = 18250 / 0.008

power = 2281250 Pa

power = 2281.25 KPa

so the minimum pressure on the piston is 2281.25 KPa