Water flovs in a pipe of diameter 150 mm. the velocity of the water is measured at a certain spot which reflects the average flow velocity. a pitot static tube has a meter coefficient of c = 1,05 and is joined to a mercury manometer indicating a reading of 167 mm. determine the flow rate of the water.

Q = 0.118 /s

Explanation:

Given :

diameter of the pipe, d = 150 mm

                                       = 0.15 m

Pitot tube co efficient, = 1.05

manometer reading is given, x = 167 mm

                                                   = 0.167 m

From manometer reading,we can find the difference between the manometer height, h

h = 2.1042 m

Now, average velocity is v =

                                            =

                                            = 6.74 m/s

Area of the pipe, A =

                                =

                                = 0.0176

Therefore, flow rate is given by, Q = A.v

                                                          = 0.0176 X 6.74

                                                          = 0.118/s

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