Ashaft of circular cross section (diameter = 3 in) is subjected to a bending moment of 3200 lb- ft. determine the bending stress at the surface of the shaft.

Explanation:

Given that

Diameter  of shaft=3 in      (1 in=0.0254 m)

Bending moment=3200 lb-ft      (1 lb-ft=1.35 N-m)

We know that bending stress in circular shaft given as

Where M is the bending moment and d is the diameter of shaft.

Given that M=4338.61 N-m

            d=0.0672 m

Now by putting the values

So  

how is this a question? in order for me to answer it i have to understand the question

explanation:

the clapeyron equation (also called the clausius-clapeyron equation) relates the slope of a reaction line on a phase diagram to fundamental thermodynamic properties.

explanation: