Aman releases a stone (at rest, vo=0) from the top of a tower. during the last second of its travel, the stone falls through a distance of (9/25)h, where h is the tower's height. find h. acceleration due to gravity, g=9.8 m/s². assume no air resistance.

Height of tower equals 122.5 meters.

Explanation:

Since the height of the tower is 'H' the total time of fall of stone 't' is calculated using second equation of kinematics as

Since the distance covered in last 1 second is and the total distance covered in 't' seconds is 'H' thus the distance covered in the first (t-1) seconds of the motion equals

Now by second equation of kinematics we have

Thus we have

Dividing i by ii we get

Thus from equation ii we obtain 'H' as

do you have any options?