Ahorizontal 20-mm diameter tube is to carry a laminar flow of sae 30 oil. what pressure drop. (p1-p2) is needed to produce a flow rate of 72 liters/hr?

Explanation:

Given that diameter of tube= 20 mm

flow rate = 72 lt/hr

The properties of SAE 30 oil at 30°C

We know that volume flow rate Q= AV

V= 0.064 m/s

Now lets find Reynolds number to check the type of flow

Re=7.18 So we can say that this is laminar flow and we know that pressure drop for laminar flow is given as

Now by putting the values the pressure drop for per unit length

x+2 because it just doubles hon so the pattern can actually tell you the expression.

so for example,

if x=2 then 2+2 is 4

if x=4 then 4+4 is 8

and so on and so forth.

i really hope that this makes sense and you out in a way hon: )