Find the diameter of the test cylinder in which 6660 n force is acting on it with a modulus of elasticity 110 x 103 pa. the initial length of the rod is 380 mm and elongation is 0.50 mm.

The diameter of the test cylinder should be 7.65 meters.

Explanation:

The Hooke's law relation between stress and strain is mathematically represented as

Where 'E' is modulus of elasticity of the material

Now by definition of strain we have

Applying values to obtain strain we get

Thus the stress developed in the material equals

Now by definition of stress we have

Solving for 'D' we get

answer:

50 vo; ts

explanation:

answer:

6.3 is the answer

explanation:

because it is the ex