When a 20-lb weight is suspended from a spring, the spring is stretched a distance of 1 in. determine the natural frequency and the period of vibration for a 30-lb weight attached to the same spring

natural frequency = 2.55 Hz

period of vibration = 0.3915 s

Explanation:

given data

weight = 20 lb

distance = 1 in = ft

weight = 30 lb

to find out

Determine the natural frequency and the period of vibration

solution

we first calculate here stiffness k by given formula that is

k =  ..........1

k =

k = 240 lb/ft

so

frequency =   ..................2

put here value k and mass m =

frequency =  

frequency = 16.05 rad/s

and

period of vibration =

period of vibration =

period of vibration = 0.3915 s

and

natural frequency =

natural frequency =

natural frequency = 2.55 Hz

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explanation:

answer:

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