Afootball player can sprint 40 meters in 4 sec. he has constant acceleration until he reaches his top speed at 10 meters and has constant speed after that. what is his acceleration? what is his constant speed?

1) Acceleration of player is 7.8125 .

2) Constant speed of player is 12.5 m/s.

Explanation:

Let the acceleration of the player by 'a' and let he complete the initial 10 meters in time

The initial 10 meters are case of uniformly accelerated motion and hence we can relate the above quantities using second equation of kinematics as

now since the player starts from rest hence u = 0 thus the equation can be written as

The speed the player reaches after time is obtained using first equation of kinematics as

Since the total distance traveled by the player is 40 meters hence the total time of trip is 4 seconds hence we infer that he covers 30 meters of distance at a constant speed in time of seconds

Hence we can write

Solving equation i and ii we get

from equation 'i' we obtain

Using this in equation 'ii' we get

Thus constant speed equals

the clapeyron equation (also called the clausius-clapeyron equation) relates the slope of a reaction line on a phase diagram to fundamental thermodynamic properties.

explanation: