Acylindrical specimen of some metal alloy having an elastic modulus of 126 gpa and an original cross-sectional diameter of 4.0 mm will experience only elastic deformation when a tensile load of 2380 n is applied. calculate the maximum length of the specimen before deformation if the maximum allowable elongation is 0.44 mm.

The maximum length of the specimen is 0.2927 m or 292.7 mm

Solution:

Modulus of elasticity, E = 126 GPa =

Diameter of the cross-section, D = 4.0 mm =

Force due to tension, F = 2380 N

Maximum elongation,

Now,

The maximum length of the specimen, can be calculated as follows:

The cross-sectional area,

Now, the stress on the specimen,

Now,

The strain on the specimen, :

Also, from Hooke's law:

⇒

⇒

⇒

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explanation: