Ashaft is to transmit 3.5 kw power while rotating at 350 rpm. if the shaft is made of plain carbon steel with 100 mpa yield strength, calculate: a) torque being transmitted by the shaft b) diameter of the shaft

a)T=95.5414 N.m

b)d=21.35 mm

Explanation:

Given that

P=3.5 KW

Speed N=350 RPM

Yield strength= 100 MPa

So Shear strength = 0.5 x 100 =50 MPa

We know that

Where N is the speed ,T is the torque and P is the power.

Now by putting the values

T=95.5414 N.m

T=95,541.4 N.mm

We also know that

d is the diameter of shaft

d=21.35 mm

Torque,T=95.5414 N.m

Diameter ,d=21.35 mm

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explanation:

answer:

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