Ammonia at 20 c with a quality of 50% and a total mass of 2 kg is in a rigid tank with an outlet valve at the bottom. how much saturated liquid can be removed from the tank in an isothermal process until there remains no more liquid?

16.38L

Explanation:

Through laboratory tests, thermodynamic tables were developed, these allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy etc ..)  

through prior knowledge of two other properties.

Quality is defined as the ratio between the amount of steam and liquid when a fluid is in a state of saturation, this means that since the quality is 50%, 1kg is liquid and 1kg is steam.

then to solve this problem we find the specific volume for ammonia in a saturated liquid state at 20C, and multiply it by mass (1kg)

v(amonia at 20C)=0.001638m^3/kg

m=(0.01638)(1)=0.01638m^3=16.38L

x+2 because it just doubles hon so the pattern can actually tell you the expression.

so for example,

if x=2 then 2+2 is 4

if x=4 then 4+4 is 8

and so on and so forth.

i really hope that this makes sense and you out in a way hon: )

answer:

try looking it up that is always

explanation: