Convert a barometric pressure of 28.75 in. hg at 32 f (0°c) to (a) psia (b) inches of water, (e) meters of liquid whose specific gravity is 0.8, and (d) kpa

a) 14.12psi, b) 390.86inH2O, d) 97.36kPa, d)12.42m

Explanation:

In order to do the conversions we need to use conversion rates:

a) 1psi=2.03602inHg

so:

and the same procedure is used for parts b and d:

b) 1inHg=13.595inH2O

so:

d) 1inHg=3.386kPa

so:

e)

Now part e is a little tricky since we need to review our specific gravity concept. The specific gravity is defined as the ratio between the specific weight of a substance ofver the specific weight of water.

so when solving for the specific gravity of the substance, we get that it is:

which can be used in the pressure equation:

when solving for h we get that:

when substituting equations we get that:

we know that:

and from the previous part of the problem we know the pressure in kPa, so when using this data we get that:

so:

h=12.42m

explanation:

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answer:

the answer is d

explanation: