One kind of ss-3xx steel alloy has a melting point of 1450°c. its specific heat = 0.46 j/g°c, and its heat of fusion 270 j/g. for a 200 kg block of this steel, determine how much heat is required to (a) raise its temperature from 25°c to its melting point and (b) transform it from solid to liquid phase.

a)Q=131.1 MJ

b)Q=54 MJ

Explanation:

Given that

Mass ,m=200 kg

Specific heat Cp=0.46 J/g°C

Cp=0.46 KJ/kg°C

Heat of fusion = 270 J/g

Heat of fusion = 270 KJ/kg

Melting point temperature = 1450°C

a)

Initial temperature = 25°C

Final temperature=1450°C

Heat required to rise temperature from 25°C to 1450°C.

Q= m CpΔT

Q=200 x 0.46 x (1450-25) KJ

Q=131,100 KJ

Q=131.1 MJ

b)

Heat required to transform from solid phase to liquid phase

Q= Mass x heat of fusion

Q=200 x 27 KJ

Q=54,000 KJ

Q=54 MJ

can you make it more obvious. i can't see it properly

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explanation:

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