Water at 120°c with a quality of 0.33 has its temperature raised 65°c in a constant volume process. what is the new quality and pressure? show the process in a p-v diagram.

final pressure = 0.7 MPa

quality = 20 degree super heat.

Explanation:

Given data:

water temperature 120 degree celcius

quality

we know that from saturated water temperature table . for T =120 DEGREE

we know that

      = 0.001060 + 0.33(0.89133- 0.001060)

       = 0.29485  m^3/kg

frinal temperature of water is

                                                         = 120 + 65 = 185 Degree

from saturated water temp. table

for T = 185 degree, VG = 0.17390 m^3/kg

from super heated table by interpolation

final pressure = 0.7 MPa

quality = 20 degree super heat.

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