4.71 a full-wave rectifier circuit with a 1-kω operates from a 120-v (rms) 60-hz household supply through a 6-to-1 transformer having a center-tapped secondary winding. it uses two silicon diodes that can be modeled to have a 0.7-v drop for all currents. what is the peak voltage of the rectified output? for what fraction of a cycle does each diode conduct? what is the average output voltage? what is the average current in the load?

The upper diode conduces in the odd half cycles. The lower diode conduces in the even half cycles.

Explanation:

The peak voltage after the 6 to 1 step down is . Then, the peak voltage of the rectified output is V_{d}" alt="V_{avg} = \frac{2V_{p (load)} }{\pi} = \frac{55,2 V}{\pi } = 17,6 V" />V_{d}" /> and according to the statement, the diodes can be modeled to be . Then, the peak voltage in the load is .

The upper diode conduces in the odd half cycles. The lower diode conduces in the even half cycles.

The average output voltage is calculated as:

The average current in the load is calculated as:

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explanation:

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