You have a rigid, sealed container of water and steam at a gauge pressure of 50 kpa. the initial mass of the mixture is initially 25% liquid and 75% vapor. you add heat until the mixture is pure vapor. find the final guage pressure.

The final gauge pressure is 70 kPa

Solution:

As per the question:

Gauge pressure, P = 50 kPa = 50000 Pa

Now,

The specific volume is given by:

v =

where

x = 0.75

Using saturated vapor- pressure table,

At a pressure of 50 kPa

Thus

v_{g} = 0.001030 + 0.75\times 3.2403 = 2.431255

Now,

The final gauge pressure is the pressure (saturation) which corresponds to the value of

Thus at

Final Pressure, P' = 70 kPa

answer:

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explanation: