Twenty six million gallons per day of wastewater with a do of 1.00 mg/l is discharged into a river with a do of 6.00 mg/l. if the flow rate of the river is 165 x 106 gal/d and saturation value of dissolved oxygen is 9.17 mg/l, what is the oxygen deficit he two flows? (0 points)

oxygen deficit = 3.851 mg/L

Explanation:

given data

flow rate of the river=  165 × gal/d

saturation value of dissolved oxygen = 9.17 mg/L

to find out

oxygen deficit he two flows

solution

we will apply here formula for dissolved oxygen content after dilution is

Do mix =     ..........................1

here Qw is rate of flow of waste water  i.e 26 × gal/d

(Do)w is Do of waste waster i.e 1 mg/L

Qr is aret of flow of river i.e 165 × gal/d

(Do)r is do of river water i.e 6 mg/L

so put all value in equation 1 we get

Do mix =

solve we get

Do mix = 5.319 mg/L

so

oxygen deficit =  saturation oxygen - (Do) mix     ..............2

oxygen deficit = 9.17 - 5.319

oxygen deficit = 3.851 mg/L

this is true

explanation:

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answer:

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