Aresistor is made out of a long wire having a length l. each end of the wire is attached to a termina of a battery providing a constant voltage v0. a currect i flows through the wire. if the wire were cut in half, making two wires of length l/2, and both wires were attached to the battery (the end of both wires attached to one terminal, and the other ends attached to the other terminal), what would be the total currect flowing through the two wires? a) 4i b) 2i c) i d) i/2 e) i/4

Option A

Solution:

As per the question:

Initially, voltage is

Current is 'I' A

Length of the wire is L

Now,

We know that:

          (1)

where

A = Cross sectional area of the wire

From eqn (1), if other things are taken to be constant, then

R ∝ L                 (2)

Thus

When the wire is cut into two reducing the length to

Resistance, R' =

Now, when these wires are connected as described, the connection is in parallel, therefore, the equivalent resistance of the two wires:

Now, from Ohm's law:

Since, according to the question voltage is constant, thus

I ∝

I ∝

Thus

I becomes 4I

answer:

d. attempt to find the owner, then leave your information if you cannot find them.

explanation:

d. represents both (b) and (c).

more logical as well.

b and c are to complicated.

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