subject
Engineering, 05.12.2019 21:31 estherdinhllama

The popularity of orange juice, especially as a breakfast drink, makes this beverage an important factor in the economy of orange-growing regions. most marketed juice is concentrated and frozen and then reconstituted before consumption, and some is "not-from-concentrate." although concentrated juices are less popular in the united states than they were at one time, they still have a major segment of the market for orange juice. the approaches to concentrating orange juice include evaporation, freeze concentration, and reverse osmosis. here we examine the evaporation process by focusing only on two constituents in the juice solids and water. fresh orange juice contains approximately 10 wt% solids (sugar, citric acid, and other ingredients) and frozen concentrate contains approximately 42 wt% solids. the frozen concentrate is obtained by evaporating water from the fresh juice to produce a mixture that is approximately 65 wt% solids. however, so that the flavor of the concentrate will closely approximate that of fresh juice, the concentrate from the evaporator is blended with fresh orange juice (and other additives) to produce a final concentrate that is approximately 42 wt% solids. (a) label the flowchart of this process, neglecting the vaporization of everything in the juice but water first prove that the subsystem containing the point where the bypass stream splits off from the evaporator feed has one degree of freedom. (if you think it has zero degrees, try determining the unknown variables associated with this system.) then perform the degree-of freedom analysis for the overall system, the evaporator, and the bypass-evaporator product mixing point, and write in order the equations you would solve to determine all unknown stream variables. in each equation, circle the variable for which you would solve, but don't do any calculations. (b) calculate the amount of product (42% concentrate) produced per 100 kg fresh juice fed to the process and the fraction of the feed that bypasses the evaporator. bypass mising point evaporator

ansver
Answers: 1

Another question on Engineering

question
Engineering, 04.07.2019 18:10
For the closed feedwater heater below, feedwater enters state 3 at a pressure of 2000 psia and temperature of 420 °f at a rate of ix10 ibhr. the feedwat extracted steam enters state 1 at a pressure of 1000 psia and enthalpy of 1500 btu/lbm. the extracted er leaves at an enthalpy of 528.7 btu/lbm steam leaves as a saturated liquid. (16) a) determine the mass flow rate of the extraction steam used to heat the feedwater (10) b) determine the terminal temperature difference of the closed feedwater heater
Answers: 3
question
Engineering, 04.07.2019 18:10
Which of the following components of a pid controlled accumulates the error over time and responds to system error after the error has been accumulated? a)- proportional b)- derivative c)- integral d)- on/off.
Answers: 2
question
Engineering, 04.07.2019 18:20
Describe one experiment in which the glass transition temperature and melting temperature of a totally amorphous thermoplastic material can be determined. show the relevant experimental results in a diagram which should be properly annotated with the two temperatures clearly marked. what is likely to happen to the curve in the diagram if the amorphous polymer is replaced by a thermosetting type?
Answers: 2
question
Engineering, 04.07.2019 19:10
Acircular aluminum shaft mounted in a journal is shown. the symmetric clearance gap between the shaft and journal is filled with sae 10w-30 oil at t 30°c. the shaft is caused to turn by the attached mass and cord. develop and solve a differential equation for the angular speed of the shaft as a function of time.
Answers: 2
You know the right answer?
The popularity of orange juice, especially as a breakfast drink, makes this beverage an important fa...
Questions
question
Mathematics, 31.07.2019 08:20
question
English, 31.07.2019 08:20
Questions on the website: 13722361