Determine the voltage across a 2000 pf capacitor that is storing 20 microcouloms (20 µc) of charge.

V=  10,000 V

Explanation:

Capacitance= C= 2000 pF

Charge = q = 20 μC

Relationship between voltage, charge and capacitance of a capacitor is:

Q= CV

⇒ V = Q/C

⇒ V= 20* /

⇒ V=  10,000 V

answer:

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explanation:  

an electrode is a metal whose surface serves as the location where oxidation-reduction equilibrium is established between the metal and what is in the solution.