Amass weighing 22 lb stretches a spring 4.5 in. the mass is also attached to a damper with y coefficient . determine the value of y for which the system is critically damped. assume that g=32 ft/s2. round your answer to three decimal places.

Cc= 12.7 lb.sec/ft

Explanation:

Given that

m = 22 lb

g= 32 ft/s²

x= 4.5 in

1 in = 0.083 ft

x= 0.375 ft

Spring constant ,K

K= 58.66  lb/ft

The damper coefficient for critically damped system

Cc= 12.7 lb.sec/ft

answer:

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explanation: