Abar is subjected to an axial load of magnitude 1,037 lbs. it is determined that the margin of safety (ms) is equal to 0.28. what is the magnitude of the applied load so that (ms = 0).

1327.36 lbs

Explanation:

Data provided in the question:

Magnitude axial load = 1,037 lbs

Margin of Safety (MS) = 0.28

Now,

MS = Factor of safety - 1

0.28 = Factor of safety - 1

or

Factor of safety = 1.28

also,

Factor of safety = [ Ultimate load ] ÷ [Applied load]

1.28 = Ultimate load ÷ 1,037 lbs

or

Ultimate load = 1.28 × 1,037 lbs

= 1327.36 lbs

For MS = 0

we get

0 = Factor of safety - 1

or

Factor of safety = 1

Therefore,

Factor of safety = [ Ultimate load ] ÷ [Applied load]

or

1 =  1327.36 lbs ÷ [Applied load]

or

Applied load = 1327.36 lbs

answer:

a

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