Calculate Original Oil in Place (OOIP). Suppose that from geological evidence it is known that the areal extent of an oil reservoir is 3 million sq. ft., the thickness of the pay zone (pay zone is the zone that contains producible hydrocarbons) is 40 ft., the porosity is equal to 30%, and Sw (water saturation) is 20%, and their is no Sg (free gas saturation).

OOIP = 2137173.84 stb Ans

Explanation:

OOIP = 7758 * A * h * n * (1 - Sw) / Boi

here A = area in acers , h = thickness in feet , n = porosity , Sw = water saturation,

Boi = 1.05 +( N * 0.05) bbl/stb here V= A * h =2754.8 feet3 ,   N = 27

OOIP = 7758 * 68.87 * 40 * 0.30 * ( 1 - 0.20) / ( 1.05 + ( 27 * 0.05))

OOIP = 2137173.84 stb Ans

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