The void ratio of an undisturbed soil sample is 0.55 and the moisture content is 11%. If Gs 5 2.68, determine: a. Moist unit weight b. Dry unit weight c. Degree of saturation d. Moisture content when the sample is fully saturated

Moist unit weight = 19.192 kN/m³

dry unit weight = 17.29 kN/m³

degree of saturation = 53.6 %

Moisture content = 20.52 %

Explanation:

given data

void ratio e = 0.55

moisture content ω = 11%

Gs =  2.68

unit weight of water rw = 10 kN/m³

solution

we get here first Moist unit weigh that is

Moist unit weight =      .............1

put here value

Moist unit weight =  

Moist unit weight = 19.192 kN/m³

and

now we get dry unit weight that is

dry unit weight =   ...........2

put here value

dry unit weight =  

dry unit weight = 17.29 kN/m³

and

now we get degree of saturation that is

degree of saturation =   ..............3

put here value

degree of saturation =  

degree of saturation = 0.536 = 53.6 %

and

now we get Moisture content when the sample is fully saturated it mean S = 1

Moisture content  =    .............4

put here value

Moisture content =  

Moisture content = 20.52 %

answer:

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explanation: