A reversible power cycle whose thermal efficiency is 40% receives 50 kJ by heat transfer from a hot reservoir at 600 K and rejects energy by heat transfer to a cold reservoir at temperature TC. Determine the energy rejected, in kJ, and TC, in K.

Explanation:

thermal efficiency = 40%

efficiency = (T₂ -T₁ ) / T₂ where T₂ is temperature of hot reservoir and T₁ is temperature of cold reservoir.

(600 -T₁ ) / 600 = .4

600 -T₁ = 240

T₁ = 360K

Energy converted into work = 50 x .4 = 20 kJ

heat rejected = 50 - 20 = 30 kJ

answer:

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answer:

the formula for amps is watts divided by volts. to use the chart, cover up the a with your finger and use the remaining chart calculation of w divided by v. using our sample panel data, 60 watts divided by 12 volts equals 5 amps.

explanation: