Engineering, 24.02.2020 23:51 loveyeti106838
A 2-kg ball B is traveling horizontally at 10 m/s when it strikes 2-kg ball A. Ball A is initially at rest and is attached to a spring with constant 100 N/m and an unstretched length of 1.2 m. Knowing the coefficient of restitution between A and B is 0.8 and friction between all surfaces is negligible, determine the normal force between A and the ground when it is at the bottom of the hill.
Answers: 2
![m_B v_0 = m_A v_A + m_B v_B_x + m_B v_B_t\\\\2*10=2v_A+2[v_B_n\cos(40^\circ)+6.428\sin(40^\circ)]\\\\2v_A+1.532v_B_n=11.736](/tpl/images/0522/1148/41fab.png)
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A 2-kg ball B is traveling horizontally at 10 m/s when it strikes 2-kg ball A. Ball A is initially a...
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