Solve for the reaction forces internal forces in the space truss below using the method of joints P,--600 lb 8 ft E 4ft 4ft 8 2. Solve for the internal forces in members FE and ED of the space truss below. Clearly state whether each member is in tension or compression. The small lines at the joint are links, preventing motion in that direction For clarity: G is on the z axis. A, B, and C are on the x-y plane, and D E, and F determine a plane parallel to the x-y plane 3m C 3m 0.75 x0.75 1.5m 5mm

Line joining liquid phase with liquid and solid phase mixture is known as: a) liquidus b) solidus c) tie line d) none of the mentioned

Air is to be cooled in the evaporator section of a refrigerator by passing it over a bank of 0.8-cm-outer-diameter and 0.4-m-long tubes inside which the refrigerant is evaporating at -20°c. air approaches the tube bank in the normal direction at 0°c and 1 atm with a mean velocity of 4 m/s. the tubes are arranged in-line with longitudinal and transverse pitches of sl- st 1.5 cm. there are 30 rows in the flow direction with 15 tubes in each row. determine (a) the refrigeration capacity of this system and (b) pressure drop across the tube bank. evaluate the air properties at an assumed mean temperature of -5°c and 1 atm. is this a good assumption?

Arigid tank contains 10 kg of air at 137 kpa (abs) and 21°c. more air is added to the tank until the pressure and temperature rise to 242 kpa (abs) and 32°c, respectively. determine the amount of air added to the tank. [r-0.287 kj/kg k]