Engineering, 27.02.2020 18:48 tori6886
Consider the diffusion of water vapor through a polypropylene (PP) sheet 1 mm thick. The pressures of H2O at the two faces are 2 kPa and 11 kPa, which are maintained constant. Assuming conditions of steady state, what is the diffusion flux, in [(cm3 STP)/cm2-s], at 298 K?
Answers: 1
x (cm3 STP) / 
-s
(
STP)-cm / 
x ΔP/Δx = 
/ Δx
x (cm3 STP)(cm) / 
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Consider the diffusion of water vapor through a polypropylene (PP) sheet 1 mm thick. The pressures o...
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