Consider the diffusion of water vapor through a polypropylene (PP) sheet 1 mm thick. The pressures of H2O at the two faces are 3 kPa and 9 kPa, which are maintained constant. Assuming conditions of steady state, what is the diffusion flux, in [(cm3 STP)/cm2-s], at 298 K

Explanation:

Diffusion flux of a gas, J is given by

where is permeability coefficient, P is pressure difference and x is thickness of membrane.

The pressure difference will be 10,000 Pa- 3000 Pa= 7000 Pa

At 298 K, the permeability coefficient of water vapour through polypropylene sheet is

Since the thickness of sheet is given as 1mm= 0.1 cm then

Therefore, the diffusion flux is

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explanation:

answer:

yes

explanation: