A 993-kg car starts from rest at the bottom of a drive way and has a speed of 3.00 m/s at a point where the drive way has risen a vertical height of 0.600 m. Friction and the drive force produced by the engine are the only two nonconservative forces present. Friction does -2870 J of work. How much work does the engine do

13177.34 J

Explanation:

Work done = force × distance

work done by the engine = kinetic energy + potential energy + work done friction

kinetic energy due to the car's speed = 1/2mv² = 4468.5 J

potential energy due to the height = mgh = 993 kg × 9.8 m/s² × 0.6 m = 5838.84 J

work done by friction = 2870 J

work done by engine = 5838.84 J + 2870 J + 4468.5 J = 13177.34 J

sorry what a asnns

explanation:

answer:

no man

explanation:

no i dont want it