Em 4:A water jet strikes normal to a xedplate. If diameter of the outlet of the nozzle is 8 cm, and velocity of water at the outlet is 10 m/s, calculate force required to keep the plate in place [25 points]

The force required to keep the plate in place is 251.36 N

Explanation:

Force = pressure × area

diameter (d) of the outlet of the nozzle = 8 cm = 8/100 = 0.08 m

area = πd^2/4 = 3.142×0.08^2/4 = 5.0272×10^-3 m^2

velocity of water (v) at the outlet = 10m/s

height (h) of water at the outlet = v^2/2g = 10^2/2×9.8 = 100/19.6 = 5.102 m

pressure = height × density of water × g = 5.102×1000×9.8 = 49999.6 N/m^2

Force = 49999.6 N/m^2 × 5.0272×10^-3 m^2 = 251.36 N

can you make it more obvious. i can't see it properly

answer:

okay

explanation: