A crest vertical curve is designed for 60 MPH. The initial grade is +4% and the final grade is negative. What is the elevation difference between the PVC and the high point on the curve?

The elevation difference between the PVC and the high point on the curve 0.1208 ft

Explanation:

g1 = 4.0%

    = 0.04

The elevation of curve at a distance “x”from pvc is given by

x = distance from pvc to point on curve

The highest point on vertical curve is at a distance "x" is given by

so, elevation of highest point

here,

substitute above values in "y" equation,

Algebric sum of grades = A =

As per AASHTO,for V= 60 mph, K =151 based on Stopping sight distance

Minimum length of vertical curve

We know that,

solving above equation we get, elevation distance between highest point and pvc as 0.1208 ft

answer:

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explanation: